Question

state the reason? as per given ​

Answer 1

Answer:

a) area of parellelogram

$= 60 \times 2\\ = 120 {cm}^{2}$

area of triangle ADE= area of triangle ABE

DIAGONAL DIVIDE AN PARELLOGRAM IN 2 EQUAL TRIANGLE

b)

area of triangle ABE

$\frac{1}{2} \times base \times hieght$

here

base=AB

hieght=BC

hence

1/2×AB×BC=60square cm

AB×BC=60×2

AB ×BC

$= 120 {cm}^{2}$

area of square ABCF

$120 {cm}^{2}$

c) area of triangleABE

$60 {cm}^{2}$

reason is same as in question part ( a)