Question

state the relation between critical velocity and escape velocity of orbiting satellite​

Answer 1

Answer:

The escape velocity from Earth is about 40,270 km/h (25,020 mph). The velocity of this orbit depends on the distance from the object to the center of the Earth. ... escape velocity is the minimum speed needed for an object to "break free" from the gravitational attraction of a massive body.

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Answer 2

$v_e=\sqrt{2} v_c$

Explanation:

The relation between orbital or critical velocity or the escape velocity is given by :

$v_e=\sqrt{2} v_c$

Here,

$v_e$ is escape velocity

$v_c$ is critical velocity

or

$v_c=\dfrac{v_e}{\sqrt{2} }$

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Relation between critical velocity and escape velocity of orbiting satellite​

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