CBSE BOARD X, asked by PushkarGamingYT, 8 months ago

State the relation between current (I) passing in conductor, number of electrons(n), flowing through cross section of conductor magnitude of charge on an electron(e) and time (t).

Answers

Answered by manshi007963
4

Answer:

I = Q/t

I - current flowing, Q - charge, t - time

Q = n*e (e as here these are electons)

n = 6.25*(10^18) e = 1.6*(10^-19)

Q = {6.25*(10^18)} * {1.6*(10^-19)}

Q = 1 C

t = 5*60 = 300 sec

I = 1/300 = 3.33*(10^-3) A

I = 3.33 mA

Explanation:

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