Question

State the relation between potential difference, work done and charge moved.
(b) Calculate the work done in moving a charge of 4 coulombs from a point at 220 volts to another point a
230 volts.​

Answer 1

$\large\bf\underline{Question\:1}$

State the relation between potential difference, work done and charge moved.

$\large\bf\underline{Answer}$

The relation between potential difference, work done and charge moved is given by –

$\longmapsto\begin{gathered}\pink {\boxed{\sf{V=\dfrac{W}{q}}}}\\\end{gathered}$

Where,

• $\sf V=\:Potential\:difference$

• $\sf W=\:Work\:done$

• $\sf q=\:Charge\:moved$

__________________

$\large\bf\underline{Question\:2}$

Calculate the work done in moving a charge of 4 coulombs from a point at 220 volts to another point a 230 volts

$\large\bf\underline{Answer}$

$\begin{gathered}\frak{we\;have}\begin{cases}\sf{\:\; \: Charge,q = \bf{4c}}\\\sf{ \: \: \: Potential\:at\:point,V_{A}=\bf{220\:V}}\\\sf{ \: \: \:Potential\:at\:point,V_{B} = \bf{230\:V}}\end{cases}\end{gathered}$

$\bf \: \underline{To\:find:}$

• $\sf Work\:done\:(W)=\:?$

$\longmapsto\bf \: \underline{Solution:}$

$\longmapsto\sf Potential\:difference,V=V_{B}-V_{A}$

$\longmapsto\sf Potential\:difference,V=(230-220)\:V$

$\longmapsto\sf Potential\:difference,V=10\:V$

We know that,

$\sf \boxed{\bold{\pink{Work\:done,W=V×q}}}$

$\longmapsto\sf Work\:done=(10×4)\:J$

$\longmapsto\sf Work\:done=40\:J$

$\underline{ \boxed{ \purple{\sf \: Thus,Work\:done=40\:J}}}$

___________________

Answer 2

Question 1 :-

• State the relation between potential difference, work done and charge moved.

Solution :-

• The relation between potential difference, work done and charge moved is given by –

$\large \red \bigstar \: \boxed{ \green{\bf V=\dfrac{W}{q}}}$

Where,

• $\sf V=\:Potential\:difference$

• $\sf W=\:Work\:done$

• $\sf q=\:Charge\:moved$

---------------------------------------------------------

Question 2 :-

• Calculate the work done in moving a charge of 4 coulombs from a point at 220 volts to another point a 230 volts

Given :-

$\begin{gathered}\begin{gathered}\frak{we\;have}\begin{cases}\sf{\:\; \: Charge,q = \bf{4c}}\\\sf{ \: \: \: Potential\:at\:point,V_{A}=\bf{220\:V}}\\\sf{ \: \: \:Potential\:at\:point,V_{B} = \bf{230\:V}}\end{cases}\end{gathered}\end{gathered}$

To Find :-

• $\sf Work\:done\:(W)=\:?$

Solution :-

$\large \red \bigstar \: \boxed{ \green{\bf Potential\: difference , V = V_{B}-V_{A} }}$

$\longmapsto\sf Potential\: difference , V = (230-220)\:V$

$\longmapsto\sf Potential\: difference, V = 10\:V$

We know that,

$\large \red \bigstar \: \boxed{ \green{\bf Work\:done,W=V×q}}$

$\longmapsto\sf Work\:done=(10×4)\:J$

$\longmapsto\sf Work\:done=40\:J$

$\large \therefore \: \underline{ \bf \pink{ Work\:done \: to \: move \: charge=40\:J }}$