Question

state the relation between the attitudes BC andCE respectively and isosceles triangle ABC with AB = AC​

Answer 1

Step-by-step explanation:

ABC is an isosceles triangle in which altitudes BD and CE are drawn to equal sides AC and AB respectively .

Given ABC is an isosceles triangle

Then AB=AC

∴∠ABC=∠ACB

Or ∴∠EBC=∠DCB

In ΔEBC, ΔDCB.....................(1)

∠BEC=∠CDB=90

0

BC=CB

∠EBC=∠DCB

ΔBEC≅ΔCFB.......(SAA test)

∴BD=EC

Then these altitudes are equal.

Answer 2

Step-by-step explanation:

ABC is an isosceles triangle in which altitudes BD and CE are drawn to equal sides AC and AB respectively .

Given ABC is an isosceles triangle

Then AB=AC

∴∠ABC=∠ACB

Or ∴∠EBC=∠DCB

∴∠ABC=∠ACB

Or ∴∠EBC=∠DCB

In ΔEBC, ΔDCB.....................(1)

∠BEC=∠CDB=90

In ΔEBC, ΔDCB.....................(1)

∠BEC=∠CDB=90

BC=CB

∠EBC=∠DCB

ΔBEC≅ΔCFB.......(SAA test)

∴BD=EC

Then these altitudes are equal.