Question

State the relation between the frequency v of radiation, emitted by an LED and the band gap energy E of the semiconductor used to fabricate it.

Answer 1

Answer:

The frequency v of radiation emitted by an LED is proportional to the bandgap energy E of the semiconductor used to make it. i.e.$E=h\nu$.

Explanation:

• Since the LEDs emit light only on the incident of a photon the photoelectric phenomena take place over here.

• In photoelectric phenomena, the energy is calculated as follows,

                           $E=h\nu$     (1)

         And for LED,

         E=energy of the bandgap of semiconductor used to fabricate it

         h=planck's constant=6.626×10⁻³⁴ Joule-second

         ν=frequency of incident radiation

Hence, the relation is $E=h\nu$.i.e.frequency is directly proportional to the energy.

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Answer 2

• The frequency is the number of occurrences of a repeating event per unit of time.
• In general frequency is defined as $\frac{1}{T}$.
• It describes the number of cycles of vibrations.
• The band-gap energy is the difference between the valence bond and the conduction bond of a solid material (such as an insulator or semi conductor)that consists of the range of energy values forbidden to electrons in the material.
• The frequency of emitted light depends on the bandgap energy pf p-n junction.This gap exists between the bottom of the conduction bond and the top of the valence bond .In semiconductors we can have direct or indirect band gaps.
•  The relation is ,  Eg=hv
• where Eg is the band gap energy E of the semiconductor .
• h is the planks constant.
• v is the frequency of radiation emitted.
• Hence the relation between the frequency v of radiation ,emitted by an LED and the band gap energy E of the semiconductor used to fabricate it is Eg=hv.

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