Math, asked by NandyJ9151, 1 year ago

State the relationship between the zeros and the coefficient of a quadratic polynomial and cubic polynomial

Answers

Answered by mad210203
4

The relationship between the zeros and the coefficient of polynomials is explained below.

Explanation:

  • A polynomial is defined as an algebraic expression consisting of multiple terms. There are different types of polynomials such as linear, quadratic, cubic, etc.
  • The general form of a quadratic polynomial is ax² + bx +c, where a ≠ 0.
  • There are two zeroes for quadratic polynomial.  ( α and β )
  • The relationship between the zeros and the coefficient of the quadratic polynomial is as follows:-
  • Sum of zeroes= α+β =  \frac{-b}{a} = \frac{- \,Coefficient\,\ of\,\  x }{Coefficient\,\ of\,\ x^{2}  }      
  • Product of zeroes =αβ  = \frac{c}{a} = \frac{Constant\,\ term }{Coefficient\,\ of\,\ x^{2}  }

  • The general form of a cubic polynomial of ax³ + bx²+ cx + d, where a ≠ 0.
  • There are three zeroes of a cubic polynomial.  (α, β, γ )
  • The relationship between the zeros and the coefficient of the cubic polynomial is as follows:-
  • Sum of zeroes = α+β+γ =  \frac{-b}{a} = \frac{- \,Coefficient\,\ of\,\  x^{2} }{Coefficient\,\ of\,\ x^{3}  }
  • Sum of the product of zeroes =

                                 αβ+ βγ+ γα = \frac{c}{a} =  \frac{Coefficient\,\ of\,\  x }{Coefficient\,\ of\,\ x^{3}  }

  • Product of zeroes= αβγ =  \frac{-d}{a} = \frac{-\, Constant\,\ term }{Coefficient\,\ of\,\ x^{3}  }
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