Question

state the test and one-to-one
correspondence of vertices by which
triangles are congruent and state congruent and state the remaining congruent parts.


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Answer 1

Step-by-step explanation:

In ∆MST and ∆MBT,

angle MST = angle MBT (90°)

MT is the common hypotenuse

MS=BT (Given)

By RHS congruence criterion,

∆MST ≈ ∆MBT

By CPCT,

ST=MB

angle SMT=angle TMB

angle STM=angle BTM

Hence proved