State the typical value of escape velocity for earth
Answers
Answer:
11.2 km/sec
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Answer:
The escape velocity formula is independent from the properties of the escaping object. The only thing that matters is the mass and radius of the celestial body in question: escape velocity = (2* M * G / R)^0.5. M is the mass of the planet, R is its radius, and G is the gravitational constant.THe highest escape velocity is for the planet Jupiter 59.5 KM/second.Escape Velocity, it's Formula and Derivation. When an object is thrown vertically upwards, it reaches a certain height and comes back to the earth. ... So, escape velocity is defined as the minimum initial velocity that will take a body away above the surface of a planet when it's projected vertically upwards.On the surface of the Earth, the escape velocity is about 11.2 km/s, which is approximately 33 times the speed of sound (Mach 33) and several times the muzzle velocity of a rifle bullet (up to 1.7 km/s). However, at 9,000 km altitude in "space", it is slightly less than 7.1 km/s.