Question

State the unit of self induction. The current in a circuit, drops from 10 A to 2 A in 0.1 sec. An average e.m.f. of 32 V is induced in the circuit while this happens. Find the inductance of the circuit​

Answer 1

Answer:

it's very tough

Explanation:

can you explain it

Answer 2

Answer:

The unit of self inductance is Henry. Self- inductance is denoted by 'L' and it is also called inertia of electricity as it opposes any change in current with time.

We have a formula-

∅ = Li ( where ∅= flux, i= current, L= coefficient of self inductance )

Now we know that -d∅/dt= EMF 'E'

So d∅/ dt = -L.di/dt = E

(where d∅/ dt= rate of change of flux, di/dt= change of current in a time period)

This is the fixed formula we can apply.

32 = L × ( 10 - 2 )/ 0.1 = L× 8/ 0.1 =L× 80

⇒ L = 32/ 80 = 2/5 = 0.4 H

Please note that this is given a negative value since it opposes the change of current. Check that based on your options.