State the volume occupied by 40 g. of a hydrocarbon - CH, at s.t.p. if its V.D. is 8,
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2
Answer:
State the volume occupied by 40 g. of a hydrocarbon - CH, at s.t.p. if its V.D. is 8,
Explanation:
State the volume occupied by 40 g of a hydrocarbon – CH4 at s.t.p. if its V.D. is 8. State the volume occupied by 40 g of a hydrocarbon – CH4 at s.t.p. if its V.D. is 8. Please log in or register to add a comment. = 22.4 x 40/16 = 56 lits.
Answered by
13
Answer:
56 litres is the answer
Explanation:
Molecular mass = 2 × VD
= 2 × 8 = 16
Number of moles = given mass/molecular mass
Therefore, Number of moles of hydrocarbon = 40/16
1 mole of hydrocarbon at stp = 22.4 litres
Therefore, 40/16 moles of hydrocarbon at stp = 22.4×40/16 = 56
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