Math, asked by Fizzm4767, 6 months ago

State true or false: If p is a prime number then √ is irrational

Answers

Answered by jigyasa0310

Answer:

Yeah mate. ✔️✔️

It's TRUE ...!!! ✔️✔️

If p is a prime number then ✓p is irrational.✔️✔️

$<!DOCTYPE html></p><p></p><p></p><p><html lang="en"></p><p></p><p><head></p><p></p><p><title>Tiki</title></p><p></p><p></head></p><p></p><p><body></p><p></p><p><div class="dog"> <div class="body"></div> <div class="head"></div> <div class="mouth"></div> </div> <div class="label"> <div class="ball"></div> Tiki </div></p><p></p><p><style></p><p></p><p>$tan: #BC8A63; $dgray: #666; body{ background:#D1A1AA; font-family: 'Gloria Hallelujah', cursive; } .label{ width:300px; text-align:center; color:#fff; font-size:32px; margin:-150px auto; } .dog{ width:200px; height:280px; margin:150px auto auto auto; &:hover .body::before, &:active .body::before, &:focus .body::before { animation:0.2s wag infinite; } &:hover .head, &:focus .head{ background-image: radial-gradient(circle at 50% 81%, rgb(163,66,85) 10%, transparent 1%), radial-gradient(circle at 25% 38%, $tan 7%, transparent 1%), radial-gradient(circle at 75% 38%, $tan 7%, transparent 1%), radial-gradient(circle at 25% 35%, $dgray 7%, transparent 5%), radial-gradient(circle at 75% 35%, $dgray 7%, transparent 5%), radial-gradient(circle at 110% 2%, $tan 40%, transparent 10%), radial-gradient(circle at -10% 2%, $tan 40%, transparent 10%); } &:hover .head::after, &:hover .head::before, &:focus .head::after, &:focus .head::before{ margin-top:12px; } &:hover .mouth, &:focus .mouth{ margin-top:-50px; animation:1s happyyy linear infinite; } } .head{ width:100px; height:80px; border-radius:50%; background:#fff; margin:auto; margin-top:-230px; background-image: radial-gradient(circle at 21% 33%, #fff 2%, transparent 1%), radial-gradient(circle at 71% 33%, #fff 2%, transparent 1%), radial-gradient(circle at 25% 35%, $dgray 7%, transparent 5%), radial-gradient(circle at 75% 35%, $dgray 7%, transparent 5%), radial-gradient(circle at 110% 2%, $tan 40%, transparent 10%), radial-gradient(circle at -10% 2%, $tan 40%, transparent 10%); //ears &::after, &::before{ content:''; position:absolute; background:#fff; } &::after{ width:28px; height:30px; background-image: radial-gradient(circle at 130% 35%, $tan 50%, transparent 5%); margin:5px 0 0 -15px; border-radius: 20% 20% 50% 20%; transform: skewX(-10deg) skewY(-10deg); } &::before{ width:28px; height:30px; background-image: radial-gradient(circle at -60% 5%, $tan 50%, transparent 5%); margin:5px 0 0 85px; border-radius: 20% 20% 20% 50%; transform: skewX(10deg) skewY(10deg); } } .mouth{ width:40px; height:35px; border-radius:50%; background:$tan; margin:auto; margin-top:-40px; z-index:20; background-image: radial-gradient(circle at 50% 35%, $dgray 17%, transparent 5%); &::after{ content:''; position:absolute; width:20px; height:12px; border-radius:50%; background:$dgray; background-image: radial-gradient(circle at 12% 33%, #fff 10%, transparent 1%); margin:2px 0 0 10px; } } .body{ width:100px; height:170px; background:#fff; margin:auto; border-radius:40% 40% 10% 10%; margin-top:100px; &::before{ content:''; position:absolute; width:170px; height:170px; background:#fff; border-radius:50%; z-index:-2; background-image: radial-gradient(circle at 40% 32%, #D1A1AA 70%, transparent 5%); animation:1s wag infinite; } } @keyframes wag{ 0%, 100%{ transform:rotate(0deg) translateX(20px); } 50%{ transform:rotate(-20deg); } } @keyframes happyyy{ 0%, 100%{ margin-top:-50px; } 50%{ margin-top:-52px; } } .ball{ height:40px; width:40px; border-radius:50%; background:#5CB300; background-image: radial-gradient(circle at 10% 32%, #5CB300 30%, transparent 5%), radial-gradient(circle at 20% 32%, rgba(255,255,255,0.7) 30%, transparent 5%); position:relative; margin:0px 300px auto auto; animation:2s roll ease alternate infinite; } @keyframes roll{ 0%,100%{ margin-left:0px; } 50%{ margin-left:-40px; transform:rotate(-40deg); } } </p><p></p><p></style></p><p></body></p><p></html>$

Answered by Anonymous

Answer:

true✔️

Hence,√p is irrational. Let √p be a rational number. Let,√p=a/b,where a and b are integers and b is not = 0.✔️⬇️

mark as brainliest answer ✨

Previous Question

Next Question