Question

state true or false - polynomial (x^4-1)has only 2 real zeroes

Answer 1

Answer:

False

Step-by-step explanation:

(x^4-1)= (X^2-1)(x^2+1)

Equating to 0..

(x^2-1)(x^2+1)=0

x^2=1

x^2=-1

x= sqrt(1) and sqrt(-1)