Question

state two application of universal law of gravitation

Answer 1

The Universal Law of Gravitation can be stated as:

“Every object in the universe attracts every other object with a force directed along the line of centers for the two objects that is proportional to the product of their masses and inversely proportional to the square of the separation between the two objects”.

Example of Newton’s Gravitational Law

Question: 

Calculate the gravitational force of attraction between the Earth and a 70kg man if he is standing at a sea level, a distance of 6.38 x 106m earth’s center

Answer:

m1 is the mass of the Earth which is equal to 5.98 x 1024 kg

m2 is = 70 kg

d = 6.38 x 106 m

value of G = 6.673 x 10-11 N m2/kg2

Now According to Law of Gravitation,

F=(6.673×10−11Nm2/kg2).(5.98×1024kg).(70kg)(6.38×106m)2

F = 686 N

hey there try to answer this...

The bob of a simple pendulum (mass m and length l) dropped from a horizontal position strikes a block of the same mass elastically placed on a horizontal frictionless table. The K.E. of the block will be

choose.....

2 mgl.

mgl2.

mgl.

0.

I hope it will help you...

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Answer 2

APPLICATOINS. OF UNIVERSAL LAW OF GRAVITATION ARE
It help us to

1) Determine the motion of moon around earth
2) Determine the motion of planets around sun
3) Describe the tides due to moon and ☀ sun
4) Discover new Stars and planets


hope it helps