Question

State two capacitors of capacitance 4uF and 6uF are connected in series to 100V d.c supply

Answer 1

Since you haven't given the specifications, I am assuming you want to know the charge in the circuit and hence you will need equivalence capacitance of the circuit.

We know,

1/C(eq) = 1/C(1) + 1/C(2)

C(eq) = 2.4 uF

Now, we know Q=C▵V

Hence Q=2.4x 10^-6 x 100 = 2.4x 10^-4 C