Question

State what happens when:
(a) Gypsum is heated at 373 K.
(b) Blue crystals of copper sulphate are heated.
(c) Excess of carbon dioxide gas is passed through lime water.

Answer 1

Answer:

1. when gypsum is heated at 373k then it loses its water molecule and it will converted into hard solid that is calcium sulphate hemihydrate.

• by this process plaster of Paris is form.
• 2. when blue crystals of copper sulphate is heated it will be colourless.
• 3. when excess co2 is passed through lime water then the milkiness will be disappear.

plzz plzzz mark it as brainliest

Answer 2

Let us make out the changes these substances undergoes under certain special conditions

Explanation:

(a)Gypsum : When heated at 373 k it looses all its water of crystallization and forms dead burnt plaster instead of plaster of paris .

CaSO₄.2H₂O-----> CaSO₄ + 2H₂O

Gypsum    (heated at 373K)  

CaSO₄ is dead burnt plaster .

(b) Copper sulphate crystals

When blue colour copper sulphate crystals are heated they loose their water of crystallization and turns white .

CuSO₄.5H₂O-------------> CuSO₄ +5H₂O

     (Blue)                         (White )

(c ) Excess of carbon dioxide when passes through lime water milkiness disappears because instead of forming CaCO₃ ,calcium bicarbonate  Ca(HCO₃)₂ is formed .