Question

State whether (2x + 1)(3x + 2) = 6(x - 1)(x - 2) is a quadratic equation or not?​

Answer 1

Answer:

Step-by-step explanation:

( 2x + 1 ) ( 3x + 2 )

= 2x ( 3x +2 ) + 1 ( 3x + 2 )

= 6x^2 + 4x + 3x + 2

= 6x^2 + 7x + 2

6 ( x - 1 ) ( x - 2 )

= 6 [ ( x - 1 ) ( x - 2 ) ]

= 6 [ x ( x - 2 ) - 1 ( x - 2 ) ]

= 6 [ x^2 - 2x - 1x + 2 ]

= 6 [ x^2 - 3x + 2 ]

= 6x^2 - 18x + 12

( 2x + 1 ) ( 3x + 2 ) = 6 ( x - 1 ) ( x - 2 )

6x^2 + 7x + 2 = 6x^2 - 18x + 12

6x^2 + 7x + 2 - 6x^2 + 18x - 12

6x^2 - 6x^2 + 7x + 18x + 2 - 12 = 0

0 + 25x - 10 = 0

25x - 10 = 0

25x - 10 = 0 is not in the form of ax^2 + bx + c = 0.

Therefore, it is not a quadratic equation.