Math, asked by ashwins, 1 year ago

state whether k is root of given equation y2-(k-4)y-16=0

Answers

Answered by AnUrAg12
0
y2-(k-4)y-16=0
y(2-k-4)-16=0
y(k-2)=16
k-2=16/y
k=16/y+2
k=16+2y/y

Answered by sairajkittu2102
0
2y-ky+4y=16
6y-ky=16
6y-16=ky
6-16/y=k
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