Question

State whether Rolle's theorem is
value of c:
0
f(x) = x (x - 2) e^-x in [0, 2]​

Answer 1

Answer:

hi Dr HDD FB HDD h nd DJ ha ha ad free RF

Answer 2

Explanation:

Let f be continuous on a closed interval [a,b] and differentiable on the open interval (a,b). If f(a)=f(b), then there is at least one point c in (a,b) wheref

′

(c)=0.

Given f=x

3

−3x in [−

3

,0]

⇒f

′

(x)=3x

2

−3

f

′

(c)=3c

2

−3=0

⇒c

2

=1

⇒c=−1

as c is in [−

3

,0]