Question

State whether the equation (x+1) (x-2)+x = 0 has two distinct real roots or not. Justify your

answer.

#SSR❤️​

Answer 1

Answer:

Answer

(x+1)(x−2)+x=0⇒x 2 −x+x=0

⇒x 2 −2=0D=b 2 −4ac=0−4(1)(−2)=8>0

2 −2=0D=b 2 −4ac=0−4(1)(−2)=8>0

∴ Given equation has two distinct real roots