State whether the equation (x+1) (x-2)+x = 0 has two distinct real roots or not. Justify your
answer.
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Anonymous:
yes
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7
Answer:
Answer
(x+1)(x−2)+x=0⇒x 2 −x+x=0
⇒x 2 −2=0D=b 2 −4ac=0−4(1)(−2)=8>0
2 −2=0D=b 2 −4ac=0−4(1)(−2)=8>0
∴ Given equation has two distinct real roots
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