Question

State whether the following pair of triangles are congruent or not. Give reasons for your answer​

Answer 1

Answer:

yes above 2 ∆s are congruence

Step-by-step explanation:

In ∆ABC

P=5

B=12

$h = \sqrt{ {p}^{2} + {b}^{2} } \\ = \sqrt{ {5}^{2} + 12 ^{2} } \\ = \sqrt{25 + 144} \\ = \sqrt{169} \\= 13$

NOW IN ∆ABC AND ∆PQR

AB=PQ (given)

<B=<Q (90⁰)

AC=PR (given)

∆ABC≈ ∆PQR (by RHS)

Answer 2

Yes above 2 ∆s are congruence

Step-by-step explanation:

In ∆ABC

P=5

B=12

h= √p² +b²

= √5² +12²

= √25+144

= √169

= √13

NOW IN ∆ABC AND ∆PQR

AB=PQ (given)

<B=<Q (90⁰)

AC=PR (given)

∆ABC≈ ∆PQR (by RHS)