Question

state whether the following quadratic equation ✓2x²-3/√2x+1/√2=0 have two distinct real roots ​

Answer 1

Answer: √2x^2-3/√2x+1/√2=0

=>2x^2-3x+1=0. [Multiplying the whole equation with √2]

Now,a=2,b= -3 and c=1

Discriminant,D = b^2-4ac

=>D=(-3)^2-4(2)(1)

=>D=9-8

=>D= 1

Step-by-step explanation:therefore it as two real distinct roots