state whether the following trigonometric values are positive or negative sec minus 120 degree
Answers
Given : sec minus 120 degree
sec ( - 120°)
To Find : trigonometric values are positive or negative
Solution:
sec ( - 120°)
Secx = 1/cosx
=> sec ( - 120°) = 1/cos ( - 120°)
cos(-x) = cosx
=> sec ( - 120°) = 1/cos (120°)
120° lies in 2nd Quadrant
Cos is -ve in 2nd and 3ed Quadrant
Hence cos (120°) is -ve
=> sec ( - 120°) is - ve
sec ( - 120°) is -ve (negative )
Value is - 2
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