state whether the product of two consecutive integers is even or odd
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Answered by
16
answer is even...
now let's consider n as an even number.
then the 2 no.s will be n and n+1
now multiply
n(n+1) = n²+n
here n² is even and n is also even, so their sum is also even.
now take n as an odd no.
then we got n²+ n
here n² is odd , become n is odd . and n is also odd and odd + odd gives even.
hence proved that product of 2 consecutive integers is always even
now let's consider n as an even number.
then the 2 no.s will be n and n+1
now multiply
n(n+1) = n²+n
here n² is even and n is also even, so their sum is also even.
now take n as an odd no.
then we got n²+ n
here n² is odd , become n is odd . and n is also odd and odd + odd gives even.
hence proved that product of 2 consecutive integers is always even
Vanshikaparmar:
what to solve
Answered by
2
The product would be even
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