Question

State whether The statement is True

In given recation..

2F(g) ———-> F2(g);

the signs of ∆H and ∆S are Positive ?

solve it fast

Answer 1

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The statement is Fasle ,


$\implies$∆H : Sign will be negative (- ve)

$\implies$because the energy is released in the formation of bond

$\implies$∆S : Sign will be negative (- ve)

$\implies$ because the entropy decreases when the atoms combines to form molecules.

Answer 2

ANSWER :

FALSE .

Both Δ H and Δ S will be negative.

Whenever there is a release of heat energy , the sign of Δ H is negative.

If there was absorption of energy then only ΔH is positive .

Δ S will also be negative because the products are less than reactants.

Δ S is only positive when products are more .