Chemistry, asked by Kameshwaran2334, 9 months ago

Statement-1 : A resonance hybrid is always more stable than
any of its canonical structures.
Statement-2 : This stability is due to delocalization of
electrons.

Answers

Answered by SaurabhJacob
0

The Statement-1 i.e, a resonance hybrid is always more stable than

any of its canonical structures is true because of :

1. Delocalization of electrons in the resonance hybrid.

2. Now, this is the second statement.

Thus, the 2nd statement is also true.

3. Thus Statement-1 and Statement-2 both are true and Statement-2 is the correct reason for Statement-1 .

Answered by brokendreams
0

Statement-1 and Statement-2 both are true and Statement-2 is the correct reason for Statement-1 .

Explanation:

  • Resonance is the phenomenon where there is movement of electron seen between the atoms of the molecule having vacant orbitals, pi bonds or lone pairs where electrons can move to other atoms.
  • The canonical structures are the structure that we see at a particular time.
  • But they have more energy than the hybrid structure.
  • This is because the movement of electron releases energy.
  • This decrease the internal energy of a molecule.
  • So the hybrid molecule gets more stability than the original canonical.
  • Thus Statement-1 and Statement-2 both are true and Statement-2 is the correct reason for Statement-1 .

For more information about resonance,

https://brainly.in/question/11577629

Define resonance hybrid. ​ - Brainly.in

https://brainly.in/question/11459610

properties of resonance hybrid - Brainly.in

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