Question

statement :-

40 ml of 0.1M aqueous h2s is titrated with 0.1M naoh (burette) ka1=10^-7 and ka2 = 10^-13.

question:-
what will be the ph at 40ml addition of base?

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Answer 1

In a right triangle with one angle equal to 30 the side opposing this angle is half of the hypotenuse. If BC opposing this angle is 12 cm then the hypotenuse is 24 cm. Then AB (the other side) is sqrt(24^2–12^2)=20.78 cm (Pythagora). Then the right triangle's area = semi-product of the sides = (12*20.78)/2 = 124.71 cm^2

Answer 2

Answer:

Explanation:

Here, c is concentration

alpha is degree of dissociation

Hope you know, how to solve log for pH