Question

Statement (A): The product of factors of prime number is itself.
Statement (B):(1184, 1210) and (5020, 5564) are the pairs of amicable numbers.
a) Both A and B are true
b) Both A and B are false
c) A is true and B is false
d) A is false and B is true​

Answer 1

Answer:

1. (32)⅖
2. (√3+√2)+(√3-√2)

Answer 2

Answer:

a) Both A and B are true

Step-by-step explanation:

Statement B:

(1184,1210)

sum of the divisors of 1184= 1+2+4+8+16+32+37+74+148+296+592+1184=2394

some of divisors excluding 1184= 2394 - 1184=1210

some of divisors of 1210= 1+2+5+10+11+22+55+110+121+242+605+1210+=2394

sum of divisors excluding 1210= 2394- 1210= 1184

1184 and 1210 are amicable numbers.

(5020, 5564)

sum of divisors of 5020 = 1+2+4+5+10+20+251+502+1004+1255+2510+5020=5564

sum of divisors excluding of 5020= 10,584-5020=5564

sum of divisors of 5564=

1, 2, 4, 13, 26, 52, 107, 214, 428, 1391, 2782, 5564=10,584

some of divisors excluding of 5564=

10,584-5564=5020

5020 and  5564  are amicable numbers.

please answer me brainlist.