Question

Stationary waves are produced in 10 cm long stretched string fixed at to end if the string vibrates in 5 segments and wave velocity is 20 m per second the frequency of wave is

Answer 1

answer is given above

Answer 2

Answer:

5 Hz

Explanation:

There are 5 loops or segments in 10 metre.

length of one loop = 2m

length of 2 loops   = 2 x 2 = 4 m

one complete wave is formed by one crest and a trough ie. two loops form a complete wave.

now, wavelength = 4 m  ;  v = 20 m/s

from the formula,  v=vλ ⇒ 20 = v × 4 ⇒ v = 5 Hz