Question

stationary waves of frequency 200 are formed in air . if velocity of the wave is 360 metre per second the shortest distance between antinodes will be:

Answer 1

here they are asking to find shortest distance traveled by antinodes this is equal to its wavelength
we know that,
v=nλ
where v=velocity of wave, n=frequency, λ=wavelength of wave
given ,
v=360m/s,n=200 cycles
so λ=v/n
= 360/200
=9/5
= 1.8 m