stationory point of the function f(x)=x^2+1
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Answer:
(0, f(0))
Step-by-step explanation:
Stationary point: There is no difference to the closest points.
The sentence above shows that its difference should be 0.
→ f'(x) = 2x = 0
→ x = 0
Now substitute to the function, we have y = f(0).
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