Question

Statistics

Class 10​

Answer 1

Answer:

Refer to the attachment.

Now, the cumulative frequency column is added; you may refer to it.

n = 66/2

n = 33

Value just greater than the value of "n" is 41

Thus, the median class will be 85-105

The class with highest frequency among all the classes is 85-105

Thus, the modal class will be 85-105

We need to take the upper limit of the median class and the lower limit of the modal class.

Upper limit of median class = 105

Lower limit of modal class = 85

Difference = 105 - 85

Difference = 20

Answer 2

Answer: 20

Step-by-Step explanation:

Refer to the attachment, I've given the cumulative frequency column there.

For finding the median class, we will find the value of "n"

n = $\tt {\frac {66}{2}}$

n = 33

The value of cumulative frequency which is just greater than the value of "n" is = 41

.°. The class of 41 will be the median class

Median Class = 85-105

To find the modal class, we will find the class with the highest frequency

Highest frequency = 20

.°. Modal Class = 85-105

The upper limit of median class = 105

The lower limit of modal class = 85

Difference = 105-85 = 20