Question

std 10th probability

Answer 1

Answer
Let us first write the all possible oucomes when Peter throws two different dice together.
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
∴ Total number of outcomes = 36
The favorable outcome for getting the product of numbers on the dice equal to 25 is (5, 5).
Favourable number of outcomes = 1
∴ Probability that Peter gets the product of numbers as 25
= favourable number of outcomes =1
÷ ÷
total number of outcomes. = 36

The outcomes when Rina throws a die are 1, 2, 3, 4, 5, 6.
∴ Total number of outcomes = 6
Rina throws a die and squares the number, so to get the number 25, the favourable outcome is 5.
Favourable number of outcomes = 1
∴ Probability that Rina gets the square of the number as 25
As, 1/6>1/36, so Rina has better chance to get the number 25.