Question

std 8th_________q1) Expand (x+3)2​

Answer 1

Answer:

We use the formula of (a+b)²

and we know that,

(a+b)² = a²+b²+2ab

so,

(x+3)²

==>

x² + 9 + 2×3× X

x²+6x+9

after factorise we get -

x²+6x+9

x²+3x+3x+9

x(x+3)+3(x+3)

(x+3) (x+3)

so,

zeroes are-

x+3 = 0

X = -3

here the zeroes are -3 In both case.