Question

std 9th maths In Fig.3.40, /X=62°./XYZ=54°.If YO and ZO are the bisectors of /XYZ and /XZY respectively of XYZ, find /OZY and /YOZ ​

Answer 1

Answer:

as the som of all interior angles of a triangle is 180° therefore for ∆XYZ

<x+<xyz+<xzy=180°

62°+54°+<xzy=180°

<xzy=180°-116°

<xzy=64°

<ozy=64/2=32° coz is the angle

bisector of <xzy)

similarly,<oyz=54/2=27°

using angle sum property for ∆oyz we obtain

<oyz+<yoz+<ozy=180°

27°+<yoz+32°=180°

<yoz=180°-59°

<yoz=121°