Question

Steain at 100 °C is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at 15 °C till the temperature
of the calorimeter and its contents rises to 80 °C. The mass of the steam condensed in kg is (Given specific heat capacity of
water 1 kcal kg-1 °C-1, latent heat of condensation of steam 540 kcal kg-1)
O 0.130
0 0.065
O 0.260
O 0.135​

Answer 1

Answer:

Steam

T 1 =100 C

Total mass equivalent of calorimeter =1.12kg

Temp (T i ) of calorimeter =15 0 C

Final Temp (T f ) of calorimeter =80 0 C

L s =540calg −1

540×m=1⋅12×(80−15)×1

m=0⋅13kg

Answer 2

Answer:

The mass of the steam condensed in kg is 0.130 kg.

Explanation:

Given,

Steam at 100ºC is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at 15ºC till the temperature of the calorimeter and its contents rises to 80ºC.

To find: The mass of the steam condensed in kg.

Solution:

Applying conservation of heat Energy,

Heat released by steam = heat gained by water and calorimeter

mL + m × S (100 – 80) = (1.1 + 0.02) × S × (80 – 15)

m × 540 + 20 m = 1.12 × 65

m = 0.130 kg.

Therefore, The mass of the steam condensed in kg is 0.130 kg.