Question

Steam at 100 degree celcius is passed into 20g of water acquires, a temperature of 80°C the mass of water present will be?

Answer 1

Steam at 100 degree celcius is passed into 20g of water acquires, a temperature of 80°C the mass of water present will be 22.5 gram

Answer 2

heat gained = heat lost

mL (v) + mS (w) dt = m(w) S(w) dt m × 540 + m × 1 × (100-80)

=20 × 1 × (80-10) 540 m + 20 m = 1400 m =2.5

therefore total mass of water = 20 + 2.5 =22.5 g