Question

Steam at 100°C is passed into 20 g of water at
10°C. When water acquires a temperature of 80°C,
the mass of water present will be:
[Take specific heat of water = 1 cal g-1°C-1 and
latent heat of steam = 540 cal g- 1] [AIPMT-2014]
(1) 24g
(2) 31.5 g
(3) 42.5 g
(4) 22.5 g​

Answer 1

Answer:

31.5 g

Explanation:

please mark me as brainliest answer

Answer 2

Answer:

(4) 22.5 is the correct answer...