Science, asked by sobhanbera8264, 11 months ago

Steam at 1000C is passed into 20g of water at 100C When water acquires a temperature of 800C, the mass of water present will be:
[Take specific heat of water = 1calg−10C−1 and latent heat of steam = 540calg–1]

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Answered by manishlodhi

0

Jo braket ma diya ha wahi to solution ha

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