Question

Steam at 100c is passed into 20g of water at 10c when water acquires a temperature of 80c the mass of water acquires a temperature of 80c the mass of water present will be

Answer 1

heat gained = heat lost

mL(v) +mS(w)dt = m(w)S(w)dtm×540+m×1×(100-80)

=20×1×(80-10)540m+20m

= 1400m

=2.5

therefore total mass of water =20 + 2.5 =22.5g

Answer 2

Hlew,

Here's your answer...

22.5 g

Thanks.

Sorry baby 'wink'