Question

Steam at 140 bar has an enthalpy of 3001.9 kJ/kg, find the
temperature, the specific volume and the internal energy.​

Answer 1

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Answer 2

Given info : Steam at 140 bar has an enthalpy of 3001.9 kJ/kg

To find : the temperature, specific volume and the internal energy of steam are ...

solution : at 140 bar,

heat of steam is 2642.4 kJ < 3001.9 kJ

it is clear that heat of steam is less than the actual enthalpy of 3001.9 kJ and hence steam is superheated.

from superheat tables, at 140 bar, h = 3001.9 kJ/kg at a temperature of 400°C.

so the temperature of steam is 400°C

specific volume = 0.01722 m³/kg [ from table ]

internal energy = h - pv

= 3001.9 kJ/kg - 140 bar × 0.01722 m³/kg

= 3001.9 - 140 × 10⁵ × 0.01722/10³

= 2760.82 kJ/kg

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