steam at hundred degree centigrade is added slowly to 1400 gram of water at 16 degrees centigrade until the temperature of water is released to 80 degree centigrade the mass of steam required to do this is
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Answer:
240.2g
Explanation:
Q1 = Q2
m1s1T = m2s2(T'2 - T'1)
s1=s2
m373= 1400(353-289)
m=1400*64/373
m= 240.2g
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