Steam is passed through 40 g of ice at
-10°C till temperature of mixture becomes 80°C.
Mass of mixture will be approximately
[NCERT Pg. 289]
Answers
Answered by
6
Explanation:
m1Lf+m1sdT=m2Lv
40×80+40×1×(80-0)=m2×540
6400/540=m2
m2=12
m of mixture=40+12=52
Similar questions
Geography,
1 month ago
Hindi,
1 month ago
Social Sciences,
3 months ago
Chemistry,
3 months ago
Science,
10 months ago