Question

Step-1:-
Calculate total energy per unit mass possessed by
water at a point where the pressure is
0.1x10% N/m2, velocity 0.02 m/s and height of
water level from the ground is 10 cm. (Density of
water = 1000kg/mº, g=9.8 m/s)​

Answer 1

The total energy per unit mass possessed by water at a point where the pressure is 0.1x10% N/m², velocity 0.02 m/s and height of water level from the ground  10 cm is equal to 10.9802 J/kg

• Given:

Pressure = P = 0.1 × 10⁵ N/m²

Velocity = V = 0.02 m/s

Height = h = 10 cm = 0.1 m

Density of water = ρ = 1000 kg/m³

Acceleration due to gravity = g = 9.8 m/s²

• The total energy per unit mass is given as the sum of pressure energy per unit mass, kinetic energy per unit mass and gravitational potential energy per unit mass.

• T.E = P/ρ + ( $\frac{1}{2}$ v² ) + (gh)

$T.E = \frac{0.1\times 10^5}{1000} + (\frac{1}{2} (0.02)^2) + (9.8 \times 0.1)\\\\T.E = 10+ 0.0002 + 0.98\\\\T.E = 10.9802\ J/kg$

Answer 2

Answer: 10.9 k/kg

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