Math, asked by sidsam4243, 12 hours ago

Step 1: Illustrate the problem and label it with the given measurements.Gate 3GateGate 2RoadStep 2: Determine the relationship between the segments formed andidentify the theorem that can be applied.Step 3: Write an equation based on the theorem.Step 4: Substitute the given measurements, then solve the equation.Step 5: Conclude the answer to the problem​

Answers

Answered by shaikhfurkan786788
0

Answer:

Main idea

We know that,

\rm\cdots\longrightarrow (a^{m})^{n}=a^{mn}\ \cdots[1]⋯⟶(am)n=amn ⋯[1]

We know that,

\rm\cdots\longrightarrow a^{(m^{n})}=a^{m^{n}} \cdots[2]⋯⟶a(mn)=amn⋯[2]

We know that,

\rm\cdots\longrightarrow\sqrt[\rm n]{\rm a^{\rm m}}=a^{\frac{m}{n}}\ \cdots [3]⋯⟶nam=anm ⋯[3]

We know that,

\rm\cdots\longrightarrow(ab)^{n}=a^{n}b^{n}\ \cdots[4]⋯⟶(ab)n=anbn ⋯[4]

Provided that \rm a > 0a>0 and \rm b > 0b>0 .

\rm\large\underline{\text{Explanation}}Explanation

The required expression is the following.

\rm\cdots\longrightarrow\sqrt{\dfrac{m^{n^{2}}n^{m^{2}}a^{(m+n)}}{(m+n)^{(m+n)^{2}}}}⋯⟶(m+n)(m+n)2mn2nm2a(m+n)

According to \rm[2][2] ,

\rm\cdots\longrightarrow\sqrt{\dfrac{m^{(n^{2})}n^{(m^{2})}a^{(m+n)}}{(m+n)^{(m+n)^{2}}}}⋯⟶(m+n)(m+n)2m(n2)n(m2)a(m+n)

According to \rm[3][3] ,

\rm\cdots\longrightarrow\left(\dfrac{m^{(n^{2})}n^{(m^{2})}a^{(m+n)}}{(m+n)^{(m+n)^{2}}}\right)^{\frac{1}{2}}⋯⟶((m+n)(m+n)2m(n2)n(m2)a(m+n))21

According to \rm[1][1] and \rm[4][4] ,

\rm\cdots\longrightarrow\dfrac{m^{\frac{n^{2}}{2}}n^{\frac{m^{2}}{2}}a^{\frac{(m+n)}{2}}}{(m+n)^{\frac{(m+n)^{2}}{2}}}⋯⟶(m+n)2(m+n)2m2n2n2m2a2(m+n)

The correct answer is choice (b) \rm\dfrac{m^{\frac{n^{2}}{2}}n^{\frac{m^{2}}{2}}a^{\frac{m+n}{2}}}{(m+n)^{\frac{(m+n)^{2}}{2}}}(m+n)2(m+n)2m2n2n2m2a2m+n .

\large\textrm{\underline{Extra information}}Extra information

\boxed{\textrm{Zero and negative exponents}}Zero and negative exponents

\rm\cdots\longrightarrow a^{0}=1⋯⟶a0=1

\rm\cdots\longrightarrow a^{-n}=\dfrac{1}{a^{n}}⋯⟶a−n=an1

Provided that 

Step-by-step explanation:

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