Question

Step 3:
126 = 36; Q → 3, R + 18
Divide the second divisor by the second remainder.
36 = 18; Q 2, R → 0
The divisor which does not leave a remainder
is the HCF of the given numbers.
Hence, the HCF of 126 and 540 is 18.
Step 4:
Exercise 6.3
EN
Find the HCF of the following using the short division method.
a 150, 300, 396
b. 81, 405
c. 630,1
d. 324, 378, 1890
e. 24, 112, 672
K 98,5€
&
116, 290, 580
h. 240, 1680
1
Find the HCF of the following using the long division method.
a. 84, 288
b. 780, 2652
i. 175,​

Answer 1

Answer:

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Answer 2

Answer:

Step 3:

126 = 36; Q → 3, R + 18

Divide the second divisor by the second remainder.

36 = 18; Q 2, R → 0

The divisor which does not leave a remainder

is the HCF of the given numbers.

Hence, the HCF of 126 and 540 is 18.

Step 4:

Exercise 6.3

EN

Find the HCF of the following using the short division method.

a 150, 300, 396

b. 81, 405

c. 630,1

d. 324, 378, 1890

e. 24, 112, 672

K 98,5€

&

116, 290, 580

h. 240, 1680

1

Find the HCF of the following using the long division method.

a. 84, 288

b. 780, 2652

i. 175,