Question

step by step...................​

Answer 1

Answer:

$a + b = 2 \\ a = 2 - b----- (1) \\ ab = \frac{3}{4} ----- (2) \\ from \: eq \: (2) \\ (2 - b)b = \frac{3}{4} \\ 2b - {b}^{2} = \frac{3}{4} \\ 4 {b}^{2} - 8b + 3 = 0 \\ 4 {b}^{2} - 2b - 6b + 3 = 0 \\ 2b(2b - 1) - 3(2b - 1) = 0 \\ (2b - 1)(2b - 3) = 0 \\ b = \frac{1}{2} or \: b = \frac{3}{2} \\ for \: b = \frac{1}{2} \\ a = \frac{3}{2} \\ for \: b = \frac{3}{2} \\ a = \frac{1}{2}$

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Answer 2

Answer:

a=1/2,b=3/2

Step-by-step explanation:

given,

a+b=2 -eq1

ab=3/4-eq2

In eq 1 , a+b=2 can be written as b=2-a then,

substitute b=2-a in eq 2

a(2-a)=3/4

2a-a^2=3/4

then send the left side terms to right then,

a^2-2a+3/4=0

do,lcm then ,

4a^2-8a+3=0

4a^2-2a-6a+3=0

2a(2a-1)-3(2a-1)=0

2a-1=0,

a=1/2

substitute a=1/2 in eq 1,we get,

b=3/2