Question

Step by step ans please!!
$\sqrt[4]{81^{-3} }$

Answer 1

$\sf \sqrt[4]{81^{-3} }$

$\huge\boxed{\underline{\red{\mathfrak{Solution}}}}$

According to question

$\sf \sqrt[4]{81^{-3} }\\ \sf \implies81{}^{-3}{}^{×\frac{1}{4}}\\ \sf \implies 3{}^{4}{}^{×\frac{-3}{4}}\\ \sf\implies 3{}^{-3}\\ \sf\implies\frac{1}{3{}^{3}}\\ \sf\implies\frac{1}{27}$

$\sqrt[4]{81^{-3} }=\frac{1}{27}$

☺️Hope it's help you ☺️

Answer 2

Question :---

• $\sqrt[4]{81^{-3} }$ solve it ?

Concept used :-----

a√b = b^(1/a)

(a^b)^c = a^(bc)

a^(-b) = 1/a^b

using all now, and solving the equation we get,,,,

$\sqrt[4]{81^{-3} } \\ \\ \implies \: ( {81}^{ - 3} )^{ \frac{1}{4} } \\ \\ \implies \: {(81)}^{ - 3 \times \frac{1}{4} } \\ \\ \implies {(81)}^{ \frac{ - 3}{4} } \\ \\ \implies \: {(3}^{4})^{ \frac{ - 3}{4} } \\ \\ \implies \: {3}^{4 \times \frac{ - 3}{4} } \\ \\ \implies \: {3}^{ - 3} \\ \\ \implies \: \frac{1}{ {3}^{3} } \\ \\ \implies \: \frac{1}{27}$

(Hope it helps you)