step by step explain
Q 1
Q 2
Q 3
Q 4
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Step-by-step explanation:
Q1
let the centre be O .
then ,
<AOF = 90°
and <AOF is vertically opposite to <BOE
so ,
<BOE = 90°
<COD = 180° (because it is a line )
that means ,
<COE + <BOE + <DOB = 180°
= 30° + 90° + 3y = 180°
3y = 60°
y = 60/3
y = 20
Q2
supplements are 180°
(i) 30°
30° + x = 180°
x = 150°
(ii)
79 + x = 180°
x = 101°
Q3
135° and y are interior angles lying on the same side of transversal
so 135 + y = 180°
y = 45°
I will 4th one later byee
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