Question

step by step explanation:- ​

Answer 1

Answer:

TO FIND:

Angle DCB;

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GIVEN:

Angle ABC = 50⁰

Angle CDE = 40⁰

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HOW TO SOLVE?

DE is parallel to BA.

Angle CDE = Angle CAB (Alternate angle)

Now, we will find Angle ACB.

50⁰+40⁰+Angle ACB = 180⁰ (Angle sum property of a triangle)

90⁰+ Angle ACB = 180⁰

Angle ACB = 180⁰- 90⁰

Angle ACB = 90⁰

Angle DCB + Angle ACB = 180⁰ ( Linear pair angle)

Angle DCB + 90⁰ = 180⁰

Angle DCB = 180⁰-90⁰

Angle DCB = 90⁰

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HAVE A NICE DAY!!!

Answer 2

Answer:

Given,

Angle CDE=40°, Angle ABC=50°

We know that,

Angle CDE= Angle BAC=40°(Alternate interior angles forming Z)

Angle BAC + Angle ACB + Angle CBA=180° (Angle Sum Property)

40°+ Angle ACB + 50° =180°

90° + Angle ACB = 180°

Angle ACB=180°-90°

• Therefore, Angle ACB =90°

Angle ACB + Angle DCB = 180° (forming linear pair)

90° + Angle DCB=180°

Angle DCB = 180-90

• Hence, Angle DCB = 90°

HOPE IT WILL HELP YOU